Lesson 7
Multiply Three and Fourdigit Numbers by Onedigit Numbers
Warmup: Estimation Exploration: Mysterious Area (10 minutes)
Narrative
The purpose of an Estimation Exploration is to practice the skill of estimating a reasonable answer based on experience and known information. Listen for the different ways students use their understanding of place value to estimate the area and explain why an estimate is too low or too high.
Launch
 Groups of 2
 Display the image.
 “What is an estimate that’s too high?” “Too low?” “About right?”
 1 minute: quiet think time
Activity
 “Discuss your thinking with your partner.”
 1 minute: partner discussion
 Record responses.
Student Facing
Record an estimate that is:
too low  about right  too high 

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Student Response
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Activity Synthesis
 “Is your estimate greater or less than the actual product?” (greater)
 “How could we find the actual product?” (\(6 \times 400  6 \times 5\), or subtract \(6 \times 5\) from 2,400)
Activity 1: Larger Numbers to Multiply (15 minutes)
Narrative
In this activity, students use rectangular diagrams to represent multiplication of threedigit and onedigit numbers. Though students may decompose the multidigit factor in different ways, the activity is designed to encourage them to decompose it by place value—into hundreds, tens, and ones.
Advances: Conversing, Reading
Launch
 Groups of 2
Activity
 “Work with your partner on the first problem. Then, try the rest of the activity independently.”
 2 minutes: group work time on the first problem
 5–7 minutes: independent work time on the rest of the activity
 3 minutes: partner discussion
 Monitor for students who:
 write expressions that show the multidigit factor decomposed by place value
 draw diagrams that partition the multidigit factor by place value
Student Facing
 Clare drew this diagram.

What multiplication expression can be represented by the diagram?
 Find the value of the expression. Show your reasoning.


Consider the expression \(6 \times 252\).
 Draw a diagram to represent the expression.
 Find the value of the expression. Show your reasoning.

Lin drew a diagram to represent \(3 \times 2,\!135\).
 Complete Lin’s diagram.

Write an expression to represent the value of each part of the diagram.
 Find the value of \(3 \times 2,\!135\). Show your reasoning.
Student Response
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Activity Synthesis
 Invite several students to share diagrams they drew to represent \(6\times252\).
 As each student shares, consider asking the class:
 “Where do you see the parts of the factor that was decomposed?”
 “What expressions are represented in the diagram?”
 Record expressions as students share.
Activity 2: Jada’s Errors (20 minutes)
Narrative
This activity extends students' work with multiplication to include a factor with up to four digits. Students begin to generalize that they could decompose any number into parts and multiply the parts. In this activity, students analyze a common error when multiplying. The work they look at does not apply place value understanding and therefore represents a product that is unreasonable for the given expression. When students analyze Jada's work, find her errors and explain their reasoning, they critique the reasoning of others (MP3).
Students see partial products as a way to describe the subproducts when a factor is decomposed and multiplied using the distributive property. Continue to refer to partial products in students’ diagrams and calculations by their mathematical name to build students’ intuition for their meaning (though students are not expected to use them in their reasoning).
Supports accessibility for: Conceptual Processing, VisualSpatial Processing
Launch
 Groups of 2
Activity
 “Take a few quiet minutes to analyze Jada’s errors. Then, share your thinking with your partner.”
 2 minutes: independent work time on the first problem about Jada’s diagram
 2 minutes: partner discussion
 Pause for a discussion.
 “What did Jada do correctly?” (She multiplied the nonzero digits correctly. She decomposed the 6,489 by place value, which is helpful.)
 “What did Jada miss?” (She multiplied only the nonzero digits. She didn’t account for the place value of the digits being multiplied. For example: The partial product of \(3 \times 6,\!000\) is 18,000, not 18.)
 Display and correct Jada’s diagram as a class.
 “Now complete the remaining problems independently.”
 5 minutes: independent work time on the last two problems
 Monitor for students who:
 draw diagrams that partition the multidigit factor by place value
 write expressions that show the multidigit factor decomposed by place value
Student Facing
 Jada used a diagram to multiply \(3 \times 6,\!489\) and made a few errors.
 Explain the errors Jada made.

Find the value of \(3 \times 6,\!489\). Show your reasoning.
 Find the value of \(5 \times 699\). Show your reasoning.
 Find the value of \(8 \times 4,\!973\). Show your reasoning.
Student Response
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Activity Synthesis
 Select 1–2 students to share their solutions and reasoning for finding the value of \(8\times4,\!973\).
 Consider asking students to write expressions that represent the way they found each product. For example:
\(\displaystyle 8 \times 4,\!973\\ 8 \times (4,\!000 + 900 + 70 + 3)\\ (8 \times 4,\!000) + 8 \times 900 + 8 \times 70 + 8 \times 3\\ 32,\!000 + 7,\!200 + 560 + 24\\ 39,\!784\)
Lesson Synthesis
Lesson Synthesis
“Today we used diagrams to multiply three and fourdigit numbers by onedigit numbers. Let’s compare diagrams that represent \(7 \times 2,\!129\) and \(7 \times 129\).”
Display: \(7 \times 2,\!129\) and \(7 \times 129\)
\(14,\!000 + 700 + 140 + 63 = 14,\!903\)
\(700 + 140 + 63 = 903\)
“How are the representations alike and how are they different?” (Sample responses:
 Alike: They both show the expanded form of the multidigit factor, have 7 as one of the factors, and show partial products. They both show one factor decomposed by place value or written in expanded form.
 Different: One diagram is decomposed into four parts because the factor 2,129 has four digits. The diagram shows 4 partial products. The other diagram is decomposed into 3 parts, because 129 has three digits. The diagram shows 3 partial products.)
“How would you find the value of \(7 \times 2,\!039\)?” (Think of 2,039 as \(2,\!000 + 30 + 9\) and find \((7 \times 2,\!000) + (7 \times 30) + (7 \times 9)\).)
Cooldown: The Value of the Product (5 minutes)
CoolDown
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