Lesson 15

All, Some, or No Solutions

View Student Lesson

Problem 1

For each equation, decide if it is always true or never true.

  1. \(x - 13 = x + 1\)

  2. \(x+\frac{1}{2} = x - \frac{1}{2}\)

  3. \(2(x + 3) = 5x + 6 - 3x\)

  4. \(x - 3 = 2x - 3 -x\)

  5. \(3(x-5) = 2(x-5) + x\)

Solution

For access, consult one of our IM Certified Partners.

Problem 2

Mai says that the equation \(2x + 2 = x +1\) has no solution because the left hand side is double the right hand side. Do you agree with Mai? Explain your reasoning.

Solution

For access, consult one of our IM Certified Partners.

Problem 3

  1. Write the other side of this equation so it's true for all values of \(x\): \(\frac12(6x-10) - x =\)

  2. Write the other side of this equation so it's true for no values of \(x\): \(\frac12(6x-10) - x = \)

Solution

For access, consult one of our IM Certified Partners.

Problem 4

Here is an equation that is true for all values of \(x\): \(5(x+2) = 5x+10\). Elena saw this equation and says she can tell \(20(x+2)+31=4(5x+10)+31\) is also true for any value of \(x\). How can she tell? Explain your reasoning.

Solution

For access, consult one of our IM Certified Partners.

Problem 5

Elena and Lin are trying to solve \(\frac12x+3=\frac72x+5\). Describe the change they each make to each side of the equation.

  1. Elena’s first step is to write \(3=\frac72x-\frac12x+5\).
  2. Lin’s first step is to write \(x+6=7x+10\).

Solution

For access, consult one of our IM Certified Partners.

(From Unit 4, Lesson 13.)

Problem 6

Solve each equation and check your solution.

\(3x-6=4(2-3x)-8x\)

\(\frac12z+6=\frac32(z+6)\)

\(9-7w=8w+8\)

 

Solution

For access, consult one of our IM Certified Partners.

(From Unit 4, Lesson 14.)