Lesson 15
All, Some, or No Solutions
15.1: Which One Doesn’t Belong: Equations (5 minutes)
Warm-up
The purpose of this warm-up is for students to think about equality and properties of operations when deciding whether equations are true. While there are many reasons students may decide one equation doesn’t belong, highlight responses that mention both sides of the equation being equal and ask students to explain how they can tell.
Launch
Arrange students in groups of 2–4. Give students 1 minute of quiet think time. Ask students to indicate when they have noticed one equation that does not belong and can explain why not. Give students time to share their thinking with their group. After everyone has conferred in groups, ask the group to offer at least one reason each equation doesn’t belong.
Student Facing
Which one doesn’t belong?
- \(5 + 7 = 7 + 5\)
- \(5\boldcdot 7 = 7\boldcdot 5\)
- \(2 = 7 - 5\)
- \(5 - 7 = 7 - 5\)
Student Response
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Activity Synthesis
After students have conferred in groups, invite each group to share one reason why a particular equation might not belong. Record and display the responses for all to see. After each response, ask the rest of the class if they agree or disagree. Since there is no single correct answer to the question of which equation does not belong, attend to students’ explanations and ensure the reasons given are correct.
If no students point out that 4 is not true, ask if all of the equations are true and to explain how they know.
15.2: Thinking About Solutions (15 minutes)
Activity
Students who pause to think about the structure of a complex equation before taking steps to solve it can find the most efficient solution paths and, sometimes, notice that there is no single solution to be found. The goal of this lesson is to encourage students to make this pause part of their routine and to build their skill at understanding and manipulating the structure of equations through the study of two special types of equations: ones that are always true and ones that are never true.
Students begin the activity sorting a variety of equations into categories based on their number of solutions. The activity ends with students filling in the blank side of an equation to make an equation that is always true and then again to make an equation that is never true.
Launch
Display the equation \(2t+5=2t+5\) and ask students to find a value of \(t\) that makes the equation true. After a brief quiet think time, record the responses of a few students next to the equation. Ask the class if they think there is any value of \(t\) that doesn’t work and invite students to explain why or why not. If no students suggest seeing what happens if you try to solve for \(t\), demonstrate that no matter what steps you take, the equation will always end with a statement that is always true such as \(t=t\) or \(5=5\).
Next, display the equation \(n+5=n+7\) and ask students to find a value of \(n\) that makes the equation true. After a brief quiet think time, ask the class if they think there might be a value that works and select a few students to explain why or why not. While you can try and solve for \(n\) here as with the previous example, encourage students to also use the logic that adding different values to the same value cannot result in two numbers that are the same.
Tell students that these are two special kinds of equations. The first equation has many solutions—it is true for all values of \(t\). Remind students that they encountered this type of equation during the number trick activity where one side of the equation looked complicated but it was actually the same as a very simple expression, which is why the trick worked. The second equation has no solutions—it is not true for any values of \(n\).
Arrange students in groups of 2. Give students 3–5 minutes quiet work time for the first problem, followed by partner discussion to share how they sorted the equations. Give time for partners to complete the remaining problems and follow with a whole-class discussion.
Design Principle(s): Support sense-making
Student Facing
\(\displaystyle n = n\)
\(\displaystyle 2t+6=2(t+3)\)
\(\displaystyle 3(n+1)=3n+1\)
\(\displaystyle \frac14 (20d+4)=5d\)
\(\displaystyle 5 - 9 + 3x = \text-10 + 6 + 3x\)
\(\displaystyle \frac12+x=\frac13 + x\)
\(\displaystyle y \boldcdot \text-6 \boldcdot \text-3 = 2 \boldcdot y \boldcdot 9\)
\(\displaystyle v+2=v-2\)
- Sort these equations into the two types: true for all values and true for no values.
- Write the other side of this equation so that this equation is true for all values of \(u\). \(\displaystyle 6(u-2)+2=\)
- Write the other side of this equation so that this equation is true for no values of \(u\). \(\displaystyle 6(u-2)+2=\)
Student Response
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Student Facing
Are you ready for more?
Consecutive numbers follow one right after the other. An example of three consecutive numbers is 17, 18, and 19. Another example is -100, -99, -98.
How many sets of two or more consecutive positive integers can be added to obtain a sum of 100?
Student Response
For access, consult one of our IM Certified Partners.
Anticipated Misconceptions
For the last part of the activity, students may think any expression that is not equivalent to \(6u - 10\) is a good answer. Remind students that there is another possibility: that the equation will have one solution. For example, the expression \(3u + 5\) does allow for a solution.
Activity Synthesis
Display a list of the equations from the task with space to add student ideas next to the equations. The purpose of this discussion is for students to see multiple ways of thinking about and justifying the number of solutions an equation has.
Invite students to choose an equation, say if it is true for all values or true for no values, and then justify how they know. Continue until the solutions to all the equations are known. Record a summarized version of the student’s solution next to the equation.
Next, ask students for different ways to write the other side of the equation for the second problem and add these to the display. For example, students may have distributed \(6(u-2)+2\) to get \(6u-12+2\) while others chose \(6u-10\) or something with more terms, such as \(6(u-2+1)-4\).
End the discussion by asking students for different ways to write the other side of the incomplete equation in the last question. It is important to note, if no students point it out, that all solutions should be equivalent to \(6u + \underline{ }\) where the blank represents any number other than \(\text- 10\).
Supports accessibility for: Conceptual processing; Organization
15.3: What's the Equation? (15 minutes)
Activity
In this activity, students are presented with three equations all with a missing term. They are asked to fill in the missing term to create equations with either no solution or infinitely many solutions, building on the work begun in the previous activity. At the end, students summarize what they have learned about how to tell if an equation is true for all values of \(x\) or no values of \(x\).
Launch
Give students 3–5 minutes of quiet think time followed by 3–5 minutes of partner discussion. Follow with a whole-class discussion.
Supports accessibility for: Language; Organization
Student Facing
- Complete each equation so that it is true for all values of \(x\).
- \(3x+6=3(x+\underline{\quad}\,)\)
- \(x-2=\text{-}(\,\underline{\quad}-x)\)
- \(\frac{15x-10}5=\, \underline{\quad}-2\)
- Complete each equation so that it is true for no values of \(x\).
- \(3x+6=3(x+\underline{\quad}\,)\)
- \(x-2=\text{-}(\,\underline{\quad}-x)\)
- \(\frac{15x-10}5=\, \underline{\quad}-2\)
- Describe how you know whether an equation will be true for all values of \(x\) or true for no values of \(x\).
Student Response
For access, consult one of our IM Certified Partners.
Activity Synthesis
Display each equation with a large space for writing. Under each equation, invite students to share what they used to make the equation be true for all values of \(x\) and record these for all to see. Ask:
- “What did all these answers have in common?” (There is only one possible answer for each equation that will make it be always true.)
- “What strategy did you use to figure out what that answer had to be?” (The solution had to be something that would make the right side equivalent to the left.)
Next, invite students to share what they used to make the equation true for no values of \(x\) and record these for all to see. Ask:
- “Why are there so many different solutions for these questions?” (As long as the answer wasn't what we chose in part 1, then the equation will never have a solution.)
- “What was different about Equation C?” (We had to be careful to make sure that the variable coefficient was 3 and we added a constant so that the equation wouldn't have a single solution.)
Ask students to share observations they made for the last question. If no student points it out, explain that an equation with no solution can always be rearranged or manipulated to say that two unequal values are equal (e.g., 2=3), which means the equation is never true.
Design Principle(s): Support sense-making
Lesson Synthesis
Lesson Synthesis
Ask students to think about some ways they were able to determine how many solutions there were to the equations they solved today. Invite students to share some thing they did. For example, students may suggest:
- tested different values for the variable
- applied allowable moves to generate equivalent equations
- examined the structure of the equation
Ask students to write a short letter to someone taking the class next year about what they should look for when trying to decide how many solutions an equation has. Tell students to use examples, share any struggles they had in deciding on the number of solutions, and which strategies they prefer for figuring out the number of solutions.
15.4: Cool-down - Choose Your Own Solution (5 minutes)
Cool-Down
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Student Lesson Summary
Student Facing
An equation is a statement that two expressions have an equal value. The equation
\(\displaystyle 2x = 6\)
is a true statement if \(x\) is 3:
\(\displaystyle 2\boldcdot 3 = 6\)
It is a false statement if \(x\) is 4:
\(\displaystyle 2 \boldcdot 4 = 6\)
The equation \(2x = 6\) has one and only one solution, because there is only one number (3) that you can double to get 6.
Some equations are true no matter what the value of the variable is. For example:
\(\displaystyle 2x = x + x\)
is always true, because if you double a number, that will always be the same as adding the number to itself. Equations like \(2x = x+x\) have an infinite number of solutions. We say it is true for all values of \(x\).
Some equations have no solutions. For example:
\(\displaystyle x = x+1\)
has no solutions, because no matter what the value of \(x\) is, it can’t equal one more than itself.
When we solve an equation, we are looking for the values of the variable that make the equation true. When we try to solve the equation, we make allowable moves assuming it has a solution. Sometimes we make allowable moves and get an equation like this:
\(\displaystyle 8 = 7\)
This statement is false, so it must be that the original equation had no solution at all.