Lesson 1
Lines, Angles, and Curves
Problem 1
Find the values of \(x, y,\) and \(z\).
Solution
For access, consult one of our IM Certified Partners.
Problem 2
Give an example from the image of each kind of segment.
- a diameter
- a chord that is not a diameter
- a radius
Solution
For access, consult one of our IM Certified Partners.
Problem 3
Identify whether each statement must be true, could possibly be true, or definitely can’t be true.
- A diameter is a chord.
- A radius is a chord.
- A chord is a diameter.
- A central angle measures 90\(^\circ\).
Solution
For access, consult one of our IM Certified Partners.
Problem 4
Write an equation of the altitude from vertex \(A\).
Solution
For access, consult one of our IM Certified Partners.
(From Unit 6, Lesson 17.)Problem 5
Triangle \(ABC\) has vertices at \((5,0), (1,6),\) and \((9,3)\). What is the point of intersection of the triangle’s medians?
The medians do not intersect in a single point.
\((3,3)\)
\((5,3)\)
\((3,4.5)\)
Solution
For access, consult one of our IM Certified Partners.
(From Unit 6, Lesson 16.)Problem 6
Consider the parallelogram with vertices at \((0,0), (8,0), (4,6),\) and \((12,6)\). Where do the diagonals of this parallelogram intersect?
Solution
For access, consult one of our IM Certified Partners.
(From Unit 6, Lesson 15.)Problem 7
Lines \(\ell\) and \(p\) are parallel. Select all true statements.
Triangle \(ADB\) is congruent to triangle \(CEF\).
The slope of line \(\ell\) is equal to the slope of line \(p\).
Triangle \(ADB\) is similar to triangle \(CEF\).
\(\sin(A) = \sin(C)\)
\(\cos(B) = \sin(C)\)
Solution
For access, consult one of our IM Certified Partners.
(From Unit 6, Lesson 10.)Problem 8
Mai wrote a proof that triangle \(AED\) is congruent to triangle \(CEB\). Mai's proof is incomplete. How can Mai fix her proof?
We know side \(AE\) is congruent to side \(CE\) and angle \(A\) is congruent to angle \(C\). By the Angle-Side-Angle Triangle Congruence Theorem, triangle \(AED\) is congruent to triangle \(CEB\).
Solution
For access, consult one of our IM Certified Partners.
(From Unit 2, Lesson 7.)