Lesson 13
Using the Pythagorean Theorem and Similarity
13.1: Similar, Right? (5 minutes)
Warm-up
The goal of this activity is to get students familiar with the two smaller right triangles formed by drawing an altitude to the hypotenuse of a right triangle. The activity previews the activities that students will do later in this lesson and the next. Listen to hear if students compare the two smaller triangles to the larger triangle, or make conjectures about what other proportional relationships might be present.
Student Facing
Is triangle \(ADC\) similar to triangle \(CDB\)? Explain or show your reasoning.
Student Response
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Anticipated Misconceptions
If students struggle to see which angles and sides correspond, encourage them to copy each triangle onto tracing paper and rotate them so they all have the same orientation. Colored pencils can also help students identify corresponding parts.
Activity Synthesis
Ask students how many triangles they see in the diagram. Ask them how many of the triangles are similar. If students aren’t sure, they will have more opportunities later in the lesson to untangle the diagram.
Tell students an altitude in a triangle is a line segment from a vertex to the opposite side that is perpendicular to that side.
13.2: Tangled Triangles (15 minutes)
Activity
In a subsequent lesson, students will use proportional relationships in a similar diagram to prove the Pythagorean Theorem. It’s important for students to practice seeing the relationships between the triangles formed by drawing an altitude to the hypotenuse of a right triangle. Monitor for students who:
- use the Pythagorean Theorem to find the third side length
- use the scale factor they determined to find the third side length
- use equivalent ratios to find the third side length
Launch
Design Principle(s): Cultivate conversation
Supports accessibility for: Visual-spatial processing, conceptual processing
Student Facing
- Turn your tracing paper and convince yourself all 3 triangles are similar.
- Write 3 similarity statements.
- Determine the scale factor for each pair of triangles.
- Determine the lengths of sides \(HG\), \(GF\), and \(HF\).
Student Response
For access, consult one of our IM Certified Partners.
Anticipated Misconceptions
If students struggle to find the similarity statement, have them also trace the large triangle without the altitude and then have them orient all three triangles in the same direction.
Activity Synthesis
Invite a student to share who:
- used the Pythagorean Theorem to find the third side length
- used the scale factor they determined to find the third side length
- used equivalent ratios to find the third side length
If no student used equivalent ratios, ask students to write several equivalent ratios for the three triangles. In a subsequent lesson, students will need to recognize, write, and manipulate equivalent ratios involving the same side lengths.
13.3: More Tangled Triangles (15 minutes)
Activity
In this activity, the angle measures are not given, so students need to convince themselves that the triangles in question are similar. Students may be tempted to assume they are similar simply because of the triangles in the previous diagram that looked like this, so monitor for students actively trying to convince themselves that the Angle-Angle Triangle Similarity Theorem applies in this case. Look for:
- students measuring angles (with tracing paper or protractors)
- students measuring one or two angles and calculating the rest
- students using algebraic or logical reasoning to convince themselves that the angles would be congruent
Students also get another chance to write equivalent ratios. One key thing they might notice is that a lot of the sides are in more than one ratio.
Launch
Design Principle(s): Maximize meta-awareness; Support sense-making
Supports accessibility for: Language; Social-emotional skills
Student Facing
- Convince yourself there are 3 similar triangles. Write a similarity statement for the 3 triangles.
- Write as many equations about proportional side lengths as you can.
- What do you notice about these equations?
Student Response
For access, consult one of our IM Certified Partners.
Student Facing
Are you ready for more?
Tyler says that since triangle \(ACD\) is similar to triangle \(ABC\), the length of \(CB\) is 11.96. Noah says that since \(ABC\) is a right triangle, we can use the Pythagorean Theorem. So the length of \(CB\) is 12 exactly. Do you agree with either of them? Explain or show your reasoning.
Student Response
For access, consult one of our IM Certified Partners.
Anticipated Misconceptions
If students assume the triangles are similar because the diagram looks like the previous diagrams, ask them how they know.
Activity Synthesis
Invite students to explain how they convinced themselves that triangles \(ABC, ACD, \) and \(CBD\) are similar. Select students to share their thinking in this order:
- students who used tracing paper or measured all the angles
- students who measured just one or two angles and calculated the rest
- students who used algebraic or logical reasoning to convince themselves that the angles would be congruent
After students who traced or measured share, make sure all students understand and appreciate the idea that it’s necessary to know that the triangles are similar before considering missing side lengths and that finding angle measures is important to establish the triangles are similar.
Finally, ask students to share equivalent ratios that they found. Record equivalent ratios in which the same side appears twice in a separate column, for example \(\frac{AD}{DC} = \frac{DC}{DB}\) and \(\frac{CB}{AB} = \frac{DB}{CB}\). Ask students what they notice about the equivalent ratios grouped together.
Lesson Synthesis
Lesson Synthesis
Ask students to find the measures of all of the missing angles and justify how they know. (Angle \(BCD\) measures \(58^{\circ}\) by the Triangle Angle Sum Theorem. Angle \(ACD\) measures \(32^{\circ}\) because it is the complement of angle \(BCD\). Angle \(A\) measures \(58^{\circ}\) by the Triangle Angle Sum Theorem.)
Repeat with a variable in place of the \(32^{\circ}\) angle. (Angle \(BCD\) measures \(x^{\circ}\). Angle \(ACD\) measures \(90^{\circ} - x^{\circ}\). Angle \(A\) measures \(x^{\circ}\).) Once the angles are calculated, display for all to see the triangles redrawn so they are all oriented the same way. Invite multiple students to explain why the triangles formed by drawing the altitude to the hypotenuse must be similar. Encourage students to generalize their conclusions to any right triangle with the altitude drawn to the hypotenuse. Ask students to list all of the equivalent ratios that they can among the three similar triangles. \(\left(\frac{AD}{CA} = \frac{CD}{CB} = \frac{CA}{AB}, \frac{CD}{CA} = \frac{DB}{BC} = \frac{BC}{BA} \right)\)Point out again the equivalent ratios in which one side appears twice in the same equation. Students will need to use these in a subsequent lesson to prove the Pythagorean Theorem.
Remind students that these triangles are no different than any other set of similar triangles. All the same strategies they have for reasoning about similar triangles still apply to this diagram.
13.4: Cool-down - Finding Unknown Values in Right Triangles (5 minutes)
Cool-Down
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Student Lesson Summary
Student Facing
When we draw an altitude from the hypotenuse of a right triangle, we get lots of similar triangles that can be used to find missing lengths. An altitude is a segment from one vertex of the triangle to the line containing the opposite side that is perpendicular to the opposite side. For right triangle \(PQR\) we can draw the altitude \(PS\) .
Why are triangles \(PQR\), \(SQP\), and \(SPR\) all similar to each other?
Triangles \(PQR\) and \(SQP\) are similar by the Angle-Angle Triangle Similarity Theorem because angle \(Q\) is in both triangles, and both triangles are right triangles, so angles \(RPQ\) and \(PSQ\) are congruent. Triangles \(PQR\) and \(SPR\) are similar by the Angle-Angle Triangle Similarity Theorem because angle \(R\) is in both triangles, and both triangles are right triangles, so angles \(RPQ\) and \(RSP\) are congruent. Because triangles \(SQP\) and \(SPR\) are both similar to triangle \(PQR\), they are also similar to each other.
Since the triangles \(PQR\), \(SQP\), and \(SPR\) are all similar, corresponding angles are congruent and pairs of corresponding sides are scaled copies of each other, by the same scale factor. We can use the proportionality of pairs of corresponding side lengths to find missing side lengths. For example, suppose we need to find \(PS\) and know \(RS=3\) and \(QS=7\). Since triangle \(SQP\) is similar to triangle \(SPR\), we know \(\frac{RS}{PS}=\frac{PS}{QS}\). So \(\frac{3}{PS}=\frac{PS}{7}\) and \(PS=\sqrt{21}\). Or, suppose we need to find \(SQ\) and know \(PQ=5\) and \(RQ=12\). Since triangle \(PQR\) is similar to triangle \(SQP\), we know \(\frac{RQ}{PQ}=\frac{PQ}{SQ}\). So \(\frac{12}{5}=\frac{5}{SQ}\) and \(SQ=\frac{25}{12}\).