Lesson 22
Rewriting Quadratic Expressions in Vertex Form
Problem 1
The following quadratic expressions all define the same function.
\((x + 5)(x + 3)\)
\(x^2 + 8x +15\)
\((x+4)^2 - 1\)
Select all of the statements that are true about the graph of this function.
The \(y\)-intercept is \((0, \text- 15)\).
The vertex is \((\text- 4, \text- 1)\).
The \(x\)-intercepts are \((\text- 5, 0)\) and \((\text- 3, 0)\).
The \(x\)-intercepts are \((0, 5)\) and \((0, 3)\).
The \(x\)-intercept is \((0, 15)\).
The \(y\)-intercept is \((0, 15)\).
The vertex is \((4, \text- 1)\).
Solution
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Problem 2
The following expressions all define the same quadratic function.
\((x - 4)(x + 6)\)
\(x^2 + 2x - 24\)
\((x + 1)^2 - 25\)
- What is the \(y\)-intercept of the graph of the function?
- What are the \(x\)-intercepts of the graph?
- What is the vertex of the graph?
- Sketch a graph of the function without graphing technology. Make sure the \(x\)-intercepts, \(y\)-intercept, and vertex are plotted accurately.
Solution
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Problem 3
Here is one way an expression in standard form is rewritten into vertex form.
\(\begin{align}&x^2 - 7x + 6 &\qquad &\text{original expression}\\ &x^2 - 7x + \left(\text-\frac72\right)^2 + 6 -\left(\text- \frac72\right)^2 &\quad&\text{step 1} \\ &\left(x-\frac72\right)^2 + 6-\frac{49}{4} &\quad&\text{step 2}\\ &\left(x-\frac72\right)^2 + \frac{24}{4}-\frac{49}{4} &\quad&\text{step 3}\\ &\left(x-\frac72\right)^2-\frac{25}{4} &\quad&\text{step 4} \end{align}\)
- In step 1, where did the number \(\text-\frac72\) come from?
- In step 1, why was \(\left(\text-\frac72\right)^2\) added and then subtracted?
- What happened in step 2?
- What happened in step 3?
- What does the last expression tell us about the graph of a function defined by this expression?
Solution
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Problem 4
Rewrite each quadratic expression in vertex form.
- \(d(x) = x^2 + 12x + 36\)
- \(f(x) = x^2 + 10x + 21\)
- \(g(x) = 2x^2 - 20x + 32\)
Solution
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Problem 5
- Give an example that shows that the sum of two irrational numbers can be rational.
- Give an example that shows that the sum of two irrational numbers can be irrational.
Solution
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(From Unit 7, Lesson 21.)Problem 6
- Give an example that shows that the product of two irrational numbers can be rational.
- Give an example that shows that the product of two irrational numbers can be irrational.
Solution
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(From Unit 7, Lesson 21.)Problem 7
Select all the equations with irrational solutions.
\(36=x^2\)
\(x^2=\frac14\)
\(x^2=8\)
\(2x^2=8\)
\(x^2=0\)
\(x^2=40\)
\(9=x^2-1\)
Solution
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(From Unit 7, Lesson 15.)Problem 8
- What are the coordinates of the vertex of the graph of the function defined by \(f(x)=2(x+1)^2-4\)?
- Find the coordinates of two other points on the graph.
-
Sketch the graph of \(f\).
Solution
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(From Unit 6, Lesson 16.)Problem 9
How is the graph of the equation \(y=(x-1)^2 + 4\) related to the graph of the equation \(y=x^2\)?
The graph of \(y=(x-1)^2 + 4\) is the same as the graph of \(y=x^2\) but is shifted 1 unit to the right and 4 units up.
The graph of \(y=(x-1)^2 + 4\) is the same as the graph of \(y=x^2\) but is shifted 1 unit to the left and 4 units up.
The graph of \(y=(x-1)^2 + 4\) is the same as the graph of \(y=x^2\) but is shifted 1 unit to the right and 4 units down.
The graph of \(y=(x-1)^2 + 4\) is the same as the graph of \(y=x^2\) but is shifted 1 unit to the left and 4 units down.
Solution
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(From Unit 6, Lesson 17.)