Lesson 10

Rewriting Quadratic Expressions in Factored Form (Part 4)

The practice problem answers are available at one of our IM Certified Partners

Problem 1

To write \(11x^2+17x-10\) in factored form, Diego first listed pairs of factors of -10.

\((\underline{\hspace{.25in}}+ 5)(\underline{\hspace{.25in}} + \text-2)\)

\((\underline{\hspace{.25in}}+ 2)(_\underline{\hspace{.25in}} + \text-5)\)

\((\underline{\hspace{.25in}} + 10) (\underline{\hspace{.25in}} + \text-1)\)

\((\underline{\hspace{.25in}} + 1) (\underline{\hspace{.25in}}+ \text-10)\)

  1. Use what Diego started to complete the rewriting.
  2. How did you know you’ve found the right pair of expressions? What did you look for when trying out different possibilities?

Problem 2

To rewrite \(4x^2-12x-7\) in factored form, Jada listed some pairs of factors of \(4x^2\):

\((2x+ \underline{\hspace{.25in}})(2x + \underline{\hspace{.25in}})\)

\((4x + \underline{\hspace{.25in}})(1x + \underline{\hspace{.25in}})\)

Use what Jada started to rewrite \(4x^2-12x-7\) in factored form.

Problem 3

Rewrite each quadratic expression in factored form. Then, use the zero product property to solve the equation.

  1. \(7x^2-22x+3=0\)
  2. \(4x^2+x-5=0\)
  3. \(9x^2-25=0\)

Problem 4

Han is solving the equation \(5x^2+13x-6=0\).

Here is his work:

\(\begin{align} 5x^2+13x-6 &= 0 \\ (5x-2)(x+3) &= 0\\x=2 \quad &\text{ or }\quad x=\text-3 \end{align}\)

Describe Han’s mistake. Then, find the correct solutions to the equation.

Problem 5

A picture is 10 inches wide by 15 inches long. The area of the picture, including a frame that is \(x\) inch thick, can be modeled by the function \(A(x) = (2x+10)(2x+15)\).

  1. Use function notation to write a statement that means: the area of the picture, including a frame that is 2 inches thick, is 266 square inches.
  2. What is the total area if the picture has a frame that is 4 inches thick?
(From Algebra1, Unit 7, Lesson 1.)

Problem 6

To solve the equation \(0 = 4x^2 -28x + 39\), Elena uses technology to graph the function \(f(x) = 4x^2 -28x + 39\). She finds that the graph crosses the \(x\)-axis at \((1.919,0)\) and \((5.081,0)\).

  1. What is the name for the points where the graph of a function crosses the \(x\)-axis?
  2. Use a calculator to compute \(f(1.919)\) and \(f(5.081)\).
  3. Explain why 1.919 and 5.081 are approximate solutions to the equation \(0 = 4x^2 -28x + 39\) and are not exact solutions.
(From Algebra1, Unit 7, Lesson 2.)

Problem 7

Which equation shows a next step in solving \(9(x-1)^2=36\) that will lead to the correct solutions?

A:

\(9(x-1) = 6 \quad \text{ or } \quad 9(x-1) = \text- 6 \)

B:

\(3(x-1)=6\)

C:

\((x-1)^2=4\)

D:

\((9x-9)^2=36\)

(From Algebra1, Unit 7, Lesson 3.)

Problem 8

Here is a description of the temperature at a certain location yesterday.

“It started out cool in the morning, but then the temperature increased until noon. It stayed the same for a while, until it suddenly dropped quickly! It got colder than it was in the morning, and after that, it was cold for the rest of the day.”
 
Sketch a graph of the temperature as a function of time.

Blank coordinate plane, grid. Horizontal axis, time, from 9 to 8, in one hour increments. Vertical axis, temperature in Fahrenheit, from 25 to 70 by 5’s.
(From Algebra1, Unit 4, Lesson 8.)

Problem 9

Technology required. The number of people, \(p\), who watch a weekly TV show is modeled by the equation \(p = 100,\!000 \boldcdot (1.1)^w\), where \(w\) is the number of weeks since the show first aired.

  1. How many people watched the show the first time it aired? Explain how you know.
  2. Use technology to graph the equation.
  3. On which week does the show first get an audience of more than 500,000 people?
(From Algebra1, Unit 5, Lesson 9.)