Lesson 10
A New Kind of Number
Problem 1
Select all the true statements.
\(\sqrt{\text-1}\) is an imaginary number.
There are no real numbers that satisfy the equation \(x=\sqrt{\text-1}\).
Because \(\sqrt{\text-1}\) is imaginary, no one does math with it.
The equation \(x^2 = \text-1\) has real solutions.
\(\sqrt{\text-1} = \text-1\) because \(\text-1 \boldcdot \text-1 = \text-1\).
Solution
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Problem 2
Plot each number on the real number line, or explain why the number is not on the real number line.
- \(\sqrt{4}\)
- \(\text- \sqrt{4}\)
- \(\sqrt{\text-4}\)
- \(\sqrt{8}\)
- \(\text- \sqrt{8}\)
- \(\sqrt{\text-8}\)
Solution
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Problem 3
Explain why \((x-4)^2=\text-9\) has no real solutions.
Solution
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Problem 4
Which value is closest to \(10^{\text- \frac12}\)?
-5
\(\frac15\)
\(\frac13\)
3
Solution
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(From Unit 3, Lesson 5.)Problem 5
Which is a solution to the equation \(\sqrt{6-x}+5=10\)?
-19
19
21
The equation has no solutions.
Solution
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(From Unit 3, Lesson 7.)Problem 6
Select all equations for which -64 is a solution.
\(\sqrt{x} = 8\)
\(\sqrt{x} = \text-8\)
\(\sqrt[3]x = 4\)
\(\sqrt[3]x = \text-4\)
\(\text-\sqrt{x}=8\)
\(\sqrt{\text-x}=8\)
Solution
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(From Unit 3, Lesson 8.)